# Is the equation x^{9} - 5x^{3} + 6 = 0 quadratic in form? Explain why or why not.

**Solution:**

An equation where the highest exponent of the variable (usually "x") is 2. It can be x² but no x³.

In other words, a quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared.

A Quadratic Equation is usually written as ax^{2} + bx + c = 0.

Where a,b and c are constants

x = unknown variable

Example: 8x^{2} + 5x - 3 = 0.

Given, the equation is x^{9} - 5x^{3} + 6 = 0

The exponent of the first term is 9 while that of the second term is 3, the square of 3.

While squaring x^{3} we get x^{6} instead of x^{9}.

Therefore, the given equation is not quadratic in form.

## Is the equation x^{9} - 5x^{3} + 6 = 0 quadratic in form? Explain why or why not.

**Summary:**

The equation x^{9} - 5x^{3} + 6 = 0 is not in quadratic form.

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