# Rearrange this expression into quadratic form, ax^{2} + bx + c = 0; 0.20 = x^{2 }/ (85 - x).

An algebraic expression in the form of ax^{2 }+ bx + c = 0 is called a quadratic equation. It has a degree value of 2.

## Answer: 0.20 = x^{2 }/ (85-x) can be arranged in the quadratic form as 5x^{2} + x - 85 = 0.

Let us proceed step by step.

**Explanation:**

Let us simplify the given equation: 0.20 = x^{2 }/ (85 - x)

⇒ 0.20 = x^{2 }/ (85 - x)

⇒ 20/100 = x^{2 }/ (85 - x)

⇒ 1/5 = x^{2 }/ (85 - x) [ reducing to lowest form]

⇒ 5x^{2} = 85 - x [ cross multiplying the terms ]

On rearranging we get 5x^{2} + x - 85 = 0

Where a = 5, b = 1 and c = -85

### Therefore, 0.20 = x^{2 }/ (85 - x) can be arranged in the quadratic form as 5x^{2} + x - 85 = 0.

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