# What is the Value of b^{2 }- 4ac for the following Equation? x^{2 }+ 5x + 4 = 0

**Solution:**

The discriminant of a polynomial is a function of its coefficients and is represented by capital ‘D’ or Delta symbol (Δ). It shows the nature of the roots of any quadratic equations where a, b, and c are real numbers.

It is represented as ‘D’

D = b^{2 }- 4ac

Where a is the coefficient of x^{2 }

b is the coefficient of x

c is a constant term

x^{2 }+ 5x + 4 = 0 [Given]

Comparing the equation with the standard form.

a = 1, b = 5 and c = 4

Substituting it in the formula

D = 5^{2 }- 4 × 1 × 4

By further calculation

D = 25 - 16

D = 9 ⇒ The quadratic roots are real and distinct

Therefore, the value of b^{2 }- 4ac is 9.

## What is the Value Of b^{2 }- 4ac for the following Equation? x^{2 }+ 5x + 4 = 0

**Summary:**

The value of b^{2 }- 4ac for the following equation x^{2 }+ 5x + 4 = 0 is 9.

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